The sum of two rational numbers is 920\dfrac{9}{20}209. If one of them is 25\dfrac{2}{5}52, find the other.
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Let xxx be the other number. 25+x=920⇒x=920−25\dfrac{2}{5} + x = \dfrac{9}{20} \\[1em] ⇒ x = \dfrac{9}{20} - \dfrac{2}{5}52+x=209⇒x=209−52
LCM of 20 and 5 is 2 x 2 x 5 = 20
⇒x=9×120×1−2×45×4⇒x=920−820⇒x=9−820⇒x=120⇒ x = \dfrac{9 \times 1}{20 \times 1} - \dfrac{2 \times 4}{5 \times 4}\\[1em] ⇒ x = \dfrac{9}{20} - \dfrac{8}{20}\\[1em] ⇒ x = \dfrac{9 - 8}{20}\\[1em] ⇒ x = \dfrac{1}{20}⇒x=20×19×1−5×42×4⇒x=209−208⇒x=209−8⇒x=201
The sum of two rational numbers is 920\dfrac{9}{20}209, if one of them is 25\dfrac{2}{5}52, the other number is 120\dfrac{1}{20}201
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Subtract:
−58\dfrac{-5}{8}8−5 from −1316\dfrac{-13}{16}16−13
−922\dfrac{-9}{22}22−9 from 533\dfrac{5}{33}335
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