Three terms are in G.P., whose product is 27. The middle term is :

1. -3

2. 3

3. -3 and 3

4. -3 or 3

The common ratio of a G.P., whose 4^th term is 27 and 6^th term is 243; is :

1. 9

2. 3

3. $\dfrac{1}{3}$

4. $\dfrac{1}{9}$

G.P. : $\dfrac{2}{9}, \dfrac{1}{3}, \dfrac{1}{2},…………..$

Assertion (A): 5^th of the given G.P. is $1\dfrac{1}{8}$.

Reason (R): If for a G.P., the first term is a, the common ratio is r and the number of terms = n, then sum of the first n term S_n = $\dfrac{a(r^n - 1)}{r - 1}$ for all r.

1. A is true, R is false.

2. A is false, R is true.

3. Both A and R are true and R is correct reason for A.

4. Both A and R are true and R is incorrect reason for A.

For a G.P., its fourth term = x, seventh term = y and tenth term = z.

Assertion (A): x, y and z are in G.P.

Reason (R): y² = (ar⁶)² = ar³ × ar⁹ = xz.

1. A is true, R is false.

2. A is false, R is true.

3. Both A and R are true and R is correct reason for A.

4. Both A and R are true and R is incorrect reason for A.