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Mathematics

The value of a property is increasing at the rate of 25% every year. By what percent will the value of the property increase after 3 years?

Compound Interest

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Answer

Let initial value of property be V0.

By growth formula,

V=V0(1+r100)n.V = V_0\Big(1 + \dfrac{r}{100}\Big)^n.

Substituting values we get,

V=V0(1+25100)3=V0(1+14)3=V0(54)3=V0×12564=125V064.V = V0\Big(1 + \dfrac{25}{100}\Big)^3 \\[1em] = V0\Big(1 + \dfrac{1}{4}\Big)^3 \\[1em] = V0\Big(\dfrac{5}{4}\Big)^3 \\[1em] = V0 \times \dfrac{125}{64} \\[1em] = \dfrac{125V_0}{64}.

Change in value (C) = Final value - Initial value.

C=125V064V0=125V064V064=61V064.\therefore C = \dfrac{125V0}{64} - V0 \\[1em] = \dfrac{125V0 - 64V0}{64} \\[1em] = \dfrac{61V_0}{64}.

Percentage increase = Change in valueOriginal value×100.\dfrac{\text{Change in value}}{\text{Original value}} \times 100.

Substituting values we get,

Percentage increase=61V064V0×100=61V064V0×100=610064=152516=95516%.\text{Percentage increase} = \dfrac{\dfrac{61V0}{64}}{V0} \times 100 \\[1em] = \dfrac{61V0}{64V0} \times 100 \\[1em] = \dfrac{6100}{64} \\[1em] = \dfrac{1525}{16} \\[1em] = 95\dfrac{5}{16}\%.

Hence, after 3 years the value of property will increase by 95516%.95\dfrac{5}{16}\%.

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