The value of [(14)−2+(13)−2]÷(15)−2\Big[\Big(\dfrac{1}{4}\Big)^{-2} + \Big(\dfrac{1}{3}\Big)^{-2}\Big] ÷ \Big(\dfrac{1}{5}\Big)^{-2}[(41)−2+(31)−2]÷(51)−2 is:
125\dfrac{1}{25}251
1
0
625
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[(14)−2+(13)−2]÷(15)−2=[(4)2+(3)2]÷(5)2=[16+9]÷25=25÷25=1\Big[\Big(\dfrac{1}{4}\Big)^{-2} + \Big(\dfrac{1}{3}\Big)^{-2}\Big] ÷ \Big(\dfrac{1}{5}\Big)^{-2}\\[1em] = [(4)^2 + (3)^2] ÷ (5)^2\\[1em] = [16 + 9] ÷ 25\\[1em] = 25 ÷ 25\\[1em] = 1[(41)−2+(31)−2]÷(51)−2=[(4)2+(3)2]÷(5)2=[16+9]÷25=25÷25=1
Hence, option 2 is the correct option.
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If 2n−7×5n−4=12502^{n-7} \times 5^{n-4} = 12502n−7×5n−4=1250, find n.
The multiplicative inverse of (80+50)(80−50)(8^0 + 5^0)(8^0 - 5^0)(80+50)(80−50) is:
49
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If 34×93=9n3^4 \times 9^3 = 9^n34×93=9n, then the value of n is:
5
7
10
none of the above
If (56)5×(65)−4=(56)3x\Big(\dfrac{5}{6}\Big)^5 \times \Big(\dfrac{6}{5}\Big)^{-4} = \Big(\dfrac{5}{6}\Big)^{3x}(65)5×(56)−4=(65)3x, then the value of xxx is:
13\dfrac{1}{3}31
203\dfrac{20}{3}320
-3
3
