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Mathematics

The value of $\dfrac{\text{1 - tan}^2 45°}{\text{1 + tan}^2 45°}$ is equal to
tan 60°
tan 30°
sin 45°
tan 0°

Trigonometrical Ratios

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Answer

Solving,

$\Rightarrow \dfrac{\text{1 - tan}^2 45°}{\text{1 + tan}^2 45°} = \dfrac{1 - 1}{1 + 1} \\[1em] = 0 \\[1em] = \text{tan 0°}.$

Hence, Option 4 is the correct option.

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