Physics
The velocity-time graph given below shows an object moving in a straight line. The displacement and the distance travelled by the object in 6 s will respectively be :

- 8 m, 16 m
- 16 m, 8 m
- 16 m, 16 m
- 8 m, 8 m
Motion in One Dimension
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Answer
8 m, 16 m
Reason — Displacement = area of 1st rectangle - area of 2nd rectangle + area of third rectangle
= [4 x 2] - [2 x 2] + [2 x 2] = 8 m
Distance = area of 1st rectangle + area of 2nd rectangle + area of third rectangle
= [4 x 2] + [2 x 2] + [2 x 2] = 16 m
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Related Questions
The velocity-time graph given below shows:

- Uniform acceleration
- Average speed
- Uniform velocity
- All of these
In the velocity-time graph shown below, the ratio of the distance travelled by the object in the last 2 s and the distance travelled in 7 s is :

A rubber ball falls freely from a height h onto a smooth floor. After striking the floor, the ball again rises to the same height. Assume that the duration of contact of the ball with the floor is negligible. Identify the correct graph for velocity with time and height with time.
- 1.

- 2.

- 3.

- 4.

For the motion with uniform velocity, how is the distance travelled related to the time?