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Mathematics

Thirty articles are bought at ₹ 450 each. If one-third of these articles are sold at 6% loss; at what price must each of the remaining articles be sold in order to make a profit of 10% on the whole ?

Profit, Loss & Discount

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Answer

Given:

C.P. of 1 article = ₹ 450

C.P. of 30 articles = ₹ 450 x 30 = ₹ 13,500

Profit desired on the whole = 10%

Profit%=ProfitC.P×100\text{Profit\%} = \dfrac{\text{Profit}}{\text{C.P}}\times 100

Putting the values, we get

10=Profit13500×100Profit=10×13500100=135000100=135010 = \dfrac{\text{Profit}}{13500} \times 100\\[1em] \Rightarrow \text{Profit} = \dfrac{10 \times 13500}{100}\\[1em] = \dfrac{135000}{100}\\[1em] = 1350

As we know,

Profit=S.P. - C.P.\text{Profit} = \text{S.P. - C.P.}

Putting the values, we get

1350=S.P.13500S.P.=13500+1350=148501350 = \text{S.P.} - 13500\\[1em] \Rightarrow \text{S.P.} = 13500 + 1350\\[1em] = 14850

C.P. of 13\dfrac{1}{3}articles = ₹ (13×13500)\Big(\dfrac{1}{3} \times 13500\Big)

= ₹ 135003\dfrac{13500}{3}

= ₹ 45004500

Loss on it = 6%

Loss%=LossC.P×100\text{Loss\%} = \dfrac{\text{Loss}}{\text{C.P}}\times 100

Putting the values, we get

6=Loss4500×100Loss=6×4500100=27000100=2706 = \dfrac{\text{Loss}}{4500} \times 100\\[1em] \Rightarrow \text{Loss} = \dfrac{6 \times 4500}{100}\\[1em] = \dfrac{27000}{100}\\[1em] = 270

As we know,

Loss=C.P. - S.P.\text{Loss} = \text{C.P. - S.P.}

Putting the values, we get

270=4500S.PS.P.=4500270=4230270 = 4500 - \text{S.P}\\[1em] \Rightarrow \text{S.P.} = 4500 - 270\\[1em] = 4230

The S.P. of the rest of the articles = ₹ 14850 - ₹ 4230 = ₹ 10620

Total articles = 30

Two - third of articles = 23×30\dfrac{2}{3} \times 30 = 20

The S.P. of each of the 20 articles = ₹ 1062020\dfrac{10620}{20} = ₹ 531

The selling price of each of the article = ₹ 531.

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