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Mathematics

Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute were recorded and summarised as follows. Find the mean heartbeats per minute for these women, choosing a suitable method.

Number of heartbeats per minuteNumber of women
65 - 682
68 - 714
71 - 743
74 - 778
77 - 807
80 - 834
83 - 862

Statistics

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Answer

We will use step deviation method.

In the following table a is the assumed mean and h is the class size.

Here, h = 3.

By formula,

Class mark = Upper limit + Lower limit2\dfrac{\text{Upper limit + Lower limit}}{2}

Number of heartbeats per minuteNumber of women (fi)xidi = xi - aui = (xi - a)/hfiui
65 - 68266.5-9-3-6
68 - 71469.5-6-2-8
71 - 74372.5-3-1-3
74 - 778a = 75.5000
77 - 80778.5317
80 - 83481.5628
83 - 86284.5936
TotalΣfi = 30Σfiui = 4

By formula,

Mean = a + ΣfiuiΣfi×h\dfrac{Σfiui}{Σf_i} \times h

Substituting values we get :

Mean =75.5+430×3=75.5+410=75.5+0.4=75.9\text{Mean } = 75.5 + \dfrac{4}{30} \times 3 \\[1em] = 75.5 + \dfrac{4}{10} \\[1em] = 75.5 + 0.4 \\[1em] = 75.9

Hence, mean = 75.9

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