Mathematics
Three brands A, B and C of biscuits are available in packets of 12, 15 and 21 biscuits respectively. If a shopkeeper wants to buy equal number of biscuits of each brand, what is the minimum number of packets of each brand he should buy?
Number Play
2 Likes
Answer
The minimum equal number of biscuits of each brand the shopkeeper should buy is the LCM of 12, 15 and 21.
| 2 | 12, 15, 21 |
|---|---|
| 2 | 6, 15, 21 |
| 3 | 3, 15, 21 |
| 5 | 1, 5, 7 |
| 7 | 1, 1, 7 |
| 1, 1, 1 |
LCM of 12, 15 and 21 = 2 × 2 × 3 × 5 × 7 = 420.
So, the shopkeeper needs 420 biscuits of each brand.
Number of packets of brand A = 420 ÷ 12 = 35.
Number of packets of brand B = 420 ÷ 15 = 28.
Number of packets of brand C = 420 ÷ 21 = 20.
Hence, the shopkeeper should buy 35 packets of brand A, 28 packets of brand B and 20 packets of brand C.
Answered By
2 Likes
Related Questions
There are three heaps of rice weighing 120 kg, 144 kg and 204 kg. Find the maximum capacity of a bag so that the rice of each heap can be packed in exact number of bags.
Three bells are ringing continuously at intervals of 30, 36 and 45 minutes respectively. At what time will they ring together again if they ring simultaneously at 8 a.m.?
Two numbers are co-prime and their LCM is 4940. If one of the numbers is 65, find the other number.
Write 2-digit odd numbers whose sum of digits is 8.