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If three resistors 𝑅1𝑅1, 𝑅2𝑅2 and 𝑅3𝑅3 are connected in series and R1˃R2˃R3R1 ˃ R2 ˃ R3, then what is the relation between the currents 𝐼1𝐼1, 𝐼2𝐼2 and 𝐼3𝐼_3 respectively flowing through them?

  1. I1=12=I3I1 = 12 = I_3
  2. I1<I2<I3I1 \lt I2 \lt I_3
  3. I1>I2>I3I1 \gt I2 \gt I_3
  4. 1I1<1I2<1I3\dfrac {1}{I1} \lt \dfrac {1}{I2} \lt \dfrac{1}{I_3}

Current Electricity

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Answer

I1=I2=I3I1 = I2 = I_3

Reason— In a series connection, the same current flows through each component, regardless of their resistances. This happens because there is only one path for the current.
∴ Current I is the same across all resistors, So I1=I2=I3I1 = I2 = I_3

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