Triangle ABC is similar to triangle PQR. If AD and PM are corresponding medians of the two triangles, prove that: AB/PQ = AD/PM.

Given, ∆ABC ~ ∆PQR AD and PM are the medians, so BD = DC and QM = MR Since, corresponding sides of similar triangles are proportional. We can write, And, ∠ABC = ∠PQR i.e., ∠ABD = ∠PQM ∴ ∆ABD ~ ∆PQM [By SAS] Since, corresponding sides of similar triangles are proportional. . Hence, proved that .