Triangle ABC is similar to triangle PQR. If bisector of angle BAC meets BC at point D and bisector of angle QPR meets QR at point M, prove that: AB/PQ = AD/PM.

Question

KnowledgeBoat · Accepted Answer

Given, ∆ABC ~ ∆PQR and AD and PM are the angle bisectors. So, ⇒ ∠A = ∠P ⇒ ⇒ ∠BAD = ∠QPM Also, ∠ABC = ∠PQR i.e., ∠ABD = ∠PQM. ∴ ∆ABD ~ ∆PQM [By AA] Since, corresponding sides of similar triangles are proportional. . Hence, proved that .

Mathematics

Triangle ABC is similar to triangle PQR. If bisector of angle BAC meets BC at point D and bisector of angle QPR meets QR at point M, prove that: AB/PQ = AD/PM.

Similarity

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