Mathematics
The two adjacent sides of a rectangle are 3a - b and 6b - a. Find its perimeter.
Related Questions
Add the following expressions:
(i) 2x2, -5x2, -x2, 6x2
(ii) x2 - 2xy + 3y2, 5y2 + 3xy - 6x2
(iii) 2x + 9y - 7z, 3y + z - 3x, 2z - 4y - x
(iv) 2ab + 3bc - 5ca, 4bc - 3ab + 7ca, 2ca - ab - 5bc
(v) 3x3 + 2x2 - 6x + 3, 2x3 - 3x2 - x - 4, 1 + 2x - 3x2 - 4x3
(vi) 3n2 + 5mn - 6m2, 2m2 - 3mn - 4n2, 2mn - 3m2 - 7n2
(vii) 3z3 - z2 + 5, 1 - 2z + z2, 3 + 2z - z3
Simplify:
(i) 5x + 3y - 8z + 2y - 3x + 5z + z - 7y - 2x
(ii) 4x3 - 2x2 + 5x - 1 + 8x + x2 - 6x3 + 7 - 6x + 3 - 3x2 - x3
(iii) 2x2 + 3xy - 3y2 + x2 - xy + y2
(iv) 2 - 3z2 + 5yz + 7y2 - 8 + z2 - 6yz - 9y2 + 1 - 2z2 - 2yz - y2
(v) 2m - 3n + 5p + 2m + n - 2p - 3m - 4n + p
Find the perimeter of a triangle whose sides are 2y + 3z, z - y, 4y - 2z.
Subtract:
(i) 3a - 2b + 4c from 5a - 3b - 5c
(ii) 5x2 - 3xy - 7y2 from 3x2 - xy - 2y2
(iii) 3p3 - 5p2q + 2q2 from q2 + p2q - 4p3
(iv) ab - bc - ca from 3ab + 2bc - 4ca
(v) 3z3 - 2z2 + 7z - 8 from 8 - z - z2
(vi) 2abc - a2 - b2 from b2 + a2 - 2abc