Mathematics

Two cars X and Y use 1 litre of diesel to travel x km and (x + 3) km respectively. If both the cars covered a distance of 72 km, then : If car X used 4 litres of diesel more than car Y in the journey, then : 1.72/(x − 3) − 12/x = 4 2.72/(x + 3) − 12/x = 4 3.72/x − 72/(x + 3) = 4 4.72/(x − 3) − 72/(x + 3) = 4

Quadratic Equations

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