Two chords AB and CD of a circle intersect at a point P inside the circle such that AB = 12 cm, AP = 2.4 cm and PD = 7.2 cm. Find CD.
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Question

Two chords AB and CD of a circle intersect at a point P inside the circle such that AB = 12 cm, AP = 2.4 cm and PD = 7.2 cm. Find CD.

KnowledgeBoat · Accepted Answer

We know that, If two chords of a circle intersect internally, then the products of the length of segments are equal. AP × PB = CP × PD PB = AB - AP = 12 - 2.4 = 9.6 cm Substituting values we get, ⇒ 2.4 × 9.6 = CP × 7.2 ⇒ CP = ⇒ CP = 3.2 cm ⇒ CD = CP + PD = 3.2 + 7.2 = 10.4 cm Hence, CD = 10.4 cm.

Mathematics

Two chords AB and CD of a circle intersect at a point P inside the circle such that AB = 12 cm, AP = 2.4 cm and PD = 7.2 cm. Find CD.

Circles

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