Physics
Two micrometers are shown in figures given below. Give the actual reading shown provided :
(a) The least count of the instrument = 0.001 cm and zero error = +0.05 mm.
(b) The least count of the instrument = 0.001 cm and zero error = -0.021 cm.
Measurements
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Answer
(a) Given,
- Least count = 0.001 cm
- Zero error = +0.05 mm = +0.005 cm
From the figure,
Main scale reading (MSR) = 3 mm = 0.3 cm
And
21st division of the circular scale coincides with the main scale then
Circular scale reading (CSR) = Least count x 21 = 0.001 cm x 21 = 0.021 cm
Now,
Observed reading = MSR + CSR = 0.3 + 0.021 = 0.321 mm
The zero correction = -0.005 cm.
Then,
Actual reading = 0.321 - 0.005 = 0.316 cm
Hence, the actual reading is 0.316 cm.
(b) Given,
- Least count = 0.001 cm
- Zero error = -0.021 cm
From the figure,
Main scale reading (MSR) = 6 mm = 0.6 cm
And
41st division of the circular scale coincides with the main scale then
Circular scale reading (CSR) = Least count x 41 = 0.001 cm x 41 = 0.041 cm
Now,
Observed reading = MSR + CSR = 0.6 + 0.041 = 0.641 cm
The zero correction = +0.021 cm.
Then,
Actual reading = 0.641 + 0.021 = 0.662 cm
Hence, the actual reading is 0.662 cm.
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