Given,
5x−2x−65x+2x−6=4
Applying Componendo and Dividendo, we get :
⇒5x+2x−6−(5x−2x−6)5x+2x−6+5x−2x−6=4−14+1⇒5x+2x−6−5x+2x−625x=35⇒22x−625x=35⇒2x−65x=35
Squaring both sides, we get :
⇒(2x−65x)2=(35)2⇒(2x−65x)=(925)⇒9(5x)=25(2x−6)⇒45x=50x−150⇒50x−45x=150⇒5x=150⇒x=5150=30
Hence, x = 30.