Mathematics
The value of (1 + x)2(1 + y2) - (1 + x2)(1 + y)2 is:
2(x - y)(1 + xy)
(x - y)(1 - xy)
2(x - y)(1 - xy)
2(x + y)(1 - xy)
Factorisation
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Answer
Given,
⇒ (1 + x)2(1 + y2) - (1 + x2)(1 + y)2
⇒ (1 + 2x + x2)(1 + y2) - (1 + x2)(1 + 2y + y2)
⇒ (1 + y2 + 2x + 2xy2 + x2 + x2y2) - (1 + 2y + y2 + x2 + 2x2y + x2y2)
⇒ (1 + y2 + 2x + 2xy2 + x2 + x2y2 - 1 - 2y - y2 - x2 - 2x2y - x2y2)
⇒ 2x - 2y - 2x2y + 2xy2
⇒ 2(x - y) - 2xy(x - y)
⇒ (2 - 2xy)(x - y)
⇒ 2(1 - xy)(x - y).
Hence, option 3 is correct option.
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