The value of 4.2 × 10-15 + 42 × 10-16 + 4.2 × 10-14 is:
5 × 10-14
5.4 × 10-15
5.04 × 10-14
5.04 × 10-15
2 Likes
Given,
4.2 × 10-15 + 42 × 10-16 + 4.2 × 10-14
Now simplifying:
⇒10−14(4.2×10−1+42×10−2+4.2)⇒10−14(4.2×110+42×1100+4.2)⇒10−14(4.210+42100+4.2)⇒10−14(0.42+0.42+4.2)⇒5.04×10−14.\Rightarrow 10^{-14} (4.2 × 10^{-1} + 42 × 10^{-2} + 4.2) \\[1em] \Rightarrow 10^{-14} (4.2 \times \dfrac{1}{10} + 42 \times \dfrac{1}{100} + 4.2) \\[1em] \Rightarrow 10^{-14} \Big(\dfrac{4.2}{10} + \dfrac{42}{100} + 4.2\Big) \\[1em] \Rightarrow 10^{-14} (0.42 + 0.42 + 4.2) \\[1em] \Rightarrow 5.04 × 10^{-14}.⇒10−14(4.2×10−1+42×10−2+4.2)⇒10−14(4.2×101+42×1001+4.2)⇒10−14(104.2+10042+4.2)⇒10−14(0.42+0.42+4.2)⇒5.04×10−14.
Hence, option 3 is the correct option.
Answered By
Which of the following is equal to x?
x127−x57x^\dfrac{12}{7} - x^{\dfrac{5}{7}}x712−x75
(x3)23\Big(\sqrt{x^3}\Big)^{\dfrac{2}{3}}(x3)32
x127×x712x^\dfrac{12}{7} \times x^\dfrac{7}{12}x712×x127
(x4)1312\sqrt[12]{\Big(x^4\Big)^\dfrac{1}{3}}12(x4)31
On simplifying [5(813+2713)3]14\Big[5\Big(8^\dfrac{1}{3} + 27^\dfrac{1}{3}\Big)^{3}\Big]^{\dfrac{1}{4}}[5(831+2731)3]41, we get:
5
5\sqrt{5}5
10
1
The value of (2-1 × 22 × 2-3 × 24 × 2-5 × 26 × 2-7 × 28 × 2-9 × 210)-1 is:
2
16
132\dfrac{1}{32}321
32
The value of (-1)0 - (-1)1 - (-1)2 - (-1)3 - …. - (-1)10 is:
0
-1
11
