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Comparing 2x2 - 3x + 5 = 0 with ax2 + bx + c = 0 we get,
a = 2, b = -3 and c = 5.
We know that,
⇒ D = b2 - 4ac
⇒ D = (-3)2 - 4(2)(5)
⇒ D = 9 - 40
⇒ D = -31.
Hence, option 4 is the correct option.
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What is the nature of the roots of the equation, 2x2 - 6x + 3 = 0?
rational and unequal
irrational and unequal
real and equal
imaginary and unequal
If the equation, ax2 + 2x + a = 0 has two real and equal roots, then:
a = 0, 1
a = 1, 1
a = 0, -1
a = -1, 1