If 2x+35=25x+32x + \dfrac{3}{5} = \dfrac{2}{5}x + 32x+53=52x+3, then the value of x is
1
32\dfrac{3}{2}23
2
52\dfrac{5}{2}25
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We have:
=2x+35=25x+3⇒2x−25x=3−35⇒10x−2x5=15−35⇒8x5=125[Since the denominators are same, we cancel them]⇒8x=12⇒x=128⇒x=32\phantom{=} 2x + \dfrac{3}{5} = \dfrac{2}{5}x + 3 \\[1em] \Rightarrow 2x - \dfrac{2}{5}x = 3 - \dfrac{3}{5} \\[1em] \Rightarrow \dfrac{10x - 2x}{5} = \dfrac{15 - 3}{5} \\[1em] \Rightarrow \dfrac{8x}{5} = \dfrac{12}{5} \quad \text{[Since the denominators are same, we cancel them]} \\[1em] \Rightarrow 8x = 12 \\[1em] \Rightarrow x = \dfrac{12}{8} \\[1em] \Rightarrow x = \dfrac{3}{2}=2x+53=52x+3⇒2x−52x=3−53⇒510x−2x=515−3⇒58x=512[Since the denominators are same, we cancel them]⇒8x=12⇒x=812⇒x=23
Hence, option 2 is the correct option.
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