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Mathematics

If [xy2x+z2xy3z+w]=[15013]\begin{bmatrix} x - y & 2x + z \ 2x - y & 3z + w \end{bmatrix} = \begin{bmatrix} -1 & 5 \ 0 & 13 \end{bmatrix}, then the value of (x + y + z + w) is:

  1. 8

  2. 9

  3. 10

  4. 12

Matrices

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Answer

Given,

[xy2x+z2xy3z+w]=[15013]\Rightarrow \begin{bmatrix} x - y & 2x + z \ 2x - y & 3z + w \end{bmatrix} = \begin{bmatrix} -1 & 5 \ 0 & 13 \end{bmatrix}

Solving for x and y:

∴ 2x - y = 0

⇒ y = 2x …(1)

∴ x - y = -1 …(2)

Substituting value of y from equation (1) in x - y = -1, we get:

⇒ x - 2x = -1

⇒ -x = -1

⇒ x = 1.

Substituting value of x in equation(1), we get:

⇒ y = 2(1)

⇒ y = 2.

Solving for w and z:

∴ 2x + z = 5

⇒ 2(1) + z = 5

⇒ 2 + z = 5

⇒ z = 5 - 2

⇒ z = 3.

∴ 3z + w = 13

⇒ 3(3) + w = 13

⇒ 9 + w = 13

⇒ w = 13 - 9

⇒ w = 4.

∴ x + y + z + w = 1 + 2 + 3 + 4 = 10.

Hence, option 3 is the correct option.

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