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Mathematics

If [xy+2z3]+[y45]=[4912]\begin{bmatrix} x & y + 2 & z - 3 \end{bmatrix} + \begin{bmatrix} y & 4 & 5 \end{bmatrix} = \begin{bmatrix} 4 & 9 & 12 \end{bmatrix}, then the value of yz is:

  1. 24

  2. 20

  3. 36

  4. 30

Matrices

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Answer

[xy+2z3]+[y45]=[4912][x+yy+2+4z3+5]=[4912][x+yy+6z+2]=[4912]\Rightarrow \begin{bmatrix} x & y + 2 & z - 3 \end{bmatrix} + \begin{bmatrix} y & 4 & 5 \end{bmatrix} = \begin{bmatrix} 4 & 9 & 12 \end{bmatrix} \\[1em] \Rightarrow \begin{bmatrix} x + y & y + 2 + 4 & z - 3 + 5 \end{bmatrix} = \begin{bmatrix} 4 & 9 & 12 \end{bmatrix} \\[1em] \Rightarrow \begin{bmatrix} x + y & y + 6 & z + 2 \end{bmatrix} = \begin{bmatrix} 4 & 9 & 12 \end{bmatrix} \\[1em]

Solving for y and z:

∴ y + 6 = 9

⇒ y = 9 - 6

⇒ y = 3.

∴ z + 2 = 12

⇒ z = 12 - 2

⇒ z = 10.

∴ yz = 3(10) = 30.

Hence, option 4 is the correct option.

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