Mathematics

Verify each of the following :

(i) 2867 + 986 = 986 + 2867

(ii) 368 x 215 = 215 x 368

(iii) (156 + 273) + 74 = 156 + (273 + 74)

(iv) (86 x 55) x 110 = 86 x (55 x 110)

Whole Numbers

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Answer

(i) 2867 + 986 = 986 + 2867

According to the Commutative Property of Addition: a + b = b + a.

Taking L.H.S. = 2867 + 986

= 3,853

Taking R.H.S. = 986 + 2867

= 3,853

Since, L.H.S. = R.H.S.

Hence, proved that 2867 + 986 = 986 + 2867.

(ii) 368 x 215 = 215 x 368

According to the Commutative Property of Multiplication: a x b = b x a.

Taking L.H.S. = 368 x 215

= 79,120

Taking R.H.S. = 215 x 368

= 79,120

Since, L.H.S. = R.H.S.

Hence, proved that 368 x 215 = 215 x 368.

(iii) (156 + 273) + 74 = 156 + (273 + 74)

According to the Associative Property of Addition: (a + b) + c = a + (b + c).

Taking L.H.S. = (156 + 273) + 74

= 429 + 74

= 503

Taking R.H.S. = 156 + (273 + 74)

= 156 + 347

= 503

Since, L.H.S. = R.H.S.

Hence, proved that (156 + 273) + 74 = 156 + (273 + 74).

(iv) (86 x 55) x 110 = 86 x (55 x 110)

According to the Associative Property of Multiplication: (a x b) x c = a x (b x c).

Taking L.H.S. = (86 x 55) x 110

= 4730 x 110

= 5,20,300

Taking R.H.S. = 86 x (55 x 110)

= 86 x 6050

= 5,20,300

Since, L.H.S. = R.H.S.

Hence, proved that (86 x 55) x 110 = 86 x (55 x 110).

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