Water is flowing at the rate of 8 m per second through a circular pipe whose internal diameter is 2 cm, into a cylindrical tank, the radius of whose base is 40 cm. Determine the increase in the water level in 30 minutes.
Mensuration
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Question

Water is flowing at the rate of 8 m per second through a circular pipe whose internal diameter is 2 cm, into a cylindrical tank, the radius of whose base is 40 cm. Determine the increase in the water level in 30 minutes.

Mensuration

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KnowledgeBoat · Accepted Answer

Internal radius of circular pipe = Volume of water flowing through pipe per second = Area of cross section of pipe × rate of flow of water = πr2 × 8 m/s = πr2 × 8 × 100 cm/s Volume of cylindrical tank = πR2h Volume of water flowing through pipe in 30 minutes = Volume of cylindrical tank (1 minute = 60 second so, 30 minutes = 30 × 60 = 1800 s) Hence, the increase in the water level in 30 minutes is 9 m.

Mathematics

Water is flowing at the rate of 8 m per second through a circular pipe whose internal diameter is 2 cm, into a cylindrical tank, the radius of whose base is 40 cm. Determine the increase in the water level in 30 minutes.

Mensuration

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Water is flowing at the rate of 8 m per second through a circular pipe whose internal diameter is 2 cm, into a cylindrical tank, the radius of whose base is 40 cm. Determine the increase in the water level in 30 minutes.

Mensuration

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