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Mathematics

The weights of three packets are 2342\dfrac{3}{4} kg, 3133\dfrac{1}{3} kg and 5255\dfrac{2}{5} kg. Find the total weight of all the three packets.

Fractions

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Answer

Weights of three packets = 2342\dfrac{3}{4} kg, 3133\dfrac{1}{3} kg and 5255\dfrac{2}{5} kg.

Total weight = 234+313+5252\dfrac{3}{4} + 3\dfrac{1}{3} + 5\dfrac{2}{5}

LCM of 4, 3 and 5 = 60.

114+103+27511×154×15+10×203×20+27×125×1216560+20060+32460165+200+3246068960112960 kg\Rightarrow \dfrac{11}{4} + \dfrac{10}{3} + \dfrac{27}{5}\\[1em] \Rightarrow \dfrac{11 \times 15}{4 \times 15} + \dfrac{10 \times 20}{3 \times 20} + \dfrac{27 \times 12}{5 \times 12}\\[1em] \Rightarrow \dfrac{165}{60} + \dfrac{200}{60} + \dfrac{324}{60}\\[1em] \Rightarrow \dfrac{165 + 200 + 324}{60}\\[1em] \Rightarrow \dfrac{689}{60}\\[1em] \Rightarrow 11\dfrac{29}{60} \text{ kg}

Hence, the total weight of the three packets = 11296011\dfrac{29}{60} kg.

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