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What is the angle of incidence of a ray if the reflected ray is at an angle of 90° to the incident ray?

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Given,

∠i + ∠r = 90° where

∠i = angle of incident.

∠r = angle of reflection

According to the law of reflection,

∠i = ∠r

Substituting the above law in the given condition we get,

2∠i = 90°

∠i = $\dfrac{90}{2}$ = 45°

Therefore, angle of incidence = 45°.

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