Chemistry
What is the mass of 56 cm3 of carbon monoxide at S.T.P.?
(C = 12, O = 16)
Mole Concept
97 Likes
Answer
22400 cm3 of CO has mass = 12 + 16 = 28 g
∴ 56 cm3 will have mass = x 56 = 0.07 g
Answered By
39 Likes
Related Questions
Calculate the volume occupied by 320 g of sulphur dioxide at S.T.P.
[S = 32; O = 16]
Cost of Sugar (C12H22O11) is ₹40 per kg; calculate it's cost per mole.
Determine the number of molecules in a drop of water which weighs 0.09 g.
The molecular formula for elemental sulphur is S8. In a sample of 5.12 g of sulphur:
(a) How many moles of sulphur are present?
(b) How many molecules and atoms are present?