Nesting of dictionary allows you to store a dictionary inside another dictionary. Then why is following code raising error ? What can you do to correct it ?

d1 = {1 : 10, 2 : 20, 3 : 30}
d2 = {1 : 40, 2 : 50, 3 : 60}
d3 = {1 : 70, 2 : 80, 3 : 90}
d4 = {d1 : "a", d2 : "b", d3 : "c"}

Why is following code not giving correct output even when 25 is a member of the dictionary?

dic1 = {'age': 25, 'name': 'xyz', 'salary': 23450.5}  
val = dic1['age']  
if val in dic1:  
  print("This is member of the dictionary")  
else :  
  print("This is not a member of the dictionary")  

Consider the following code and then answer the questions that follow :

myDict = {'a' : 27, 'b' : 43, 'c' : 25, 'd' : 30}
valA =''
for i in myDict :
  if i > valA :
    valA = i
    valB = myDict[i]
print(valA)	            #Line1
print(valB)	            #Line2
print(30 in myDict)	    #Line3
myLst = list(myDict.items())
myLst.sort()	            #Line4
print(myLst[-1])	        #Line5

1. What output does Line 1 produce ?
2. What output does Line 2 produce ?
3. What output does Line 3 produce ?
4. What output does Line 5 produce ?
5. What is the return value from the list sort( ) function (Line 4) ?

What will be the output produced by following code ?

d1 = { 5 : "number", "a" : "string", (1, 2): "tuple" }   
print("Dictionary contents")
for x in d1.keys():	# Iterate on a key list
  print (x, ':' , d1[x], end = ' ')
  print (d1[x] * 3)
  print ( )