What should be added to -2 to get 38\dfrac{3}{8}83 ?
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Let xxx be added to -2.
−2+x=38⇒−21+x=38⇒x=38−−21-2 + x = \dfrac{3}{8}\\[1em] \Rightarrow \dfrac{-2}{1} + x = \dfrac{3}{8}\\[1em] \Rightarrow x = \dfrac{3}{8} - \dfrac{-2}{1}−2+x=83⇒1−2+x=83⇒x=83−1−2
LCM of 8 and 1 is 2 x 2 x 2 = 8
⇒x=3×18×1−−2×81×8⇒x=38−−168⇒x=3−(−16)8⇒x=3+168⇒x=198⇒x=238\Rightarrow x = \dfrac{3 \times 1}{8 \times 1} - \dfrac{-2 \times 8}{1 \times 8}\\[1em] \Rightarrow x = \dfrac{3}{8} - \dfrac{-16}{8}\\[1em] \Rightarrow x = \dfrac{3 - (-16)}{8}\\[1em] \Rightarrow x = \dfrac{3 + 16}{8}\\[1em] \Rightarrow x = \dfrac{19}{8}\\[1em] \Rightarrow x = 2\dfrac{3}{8}⇒x=8×13×1−1×8−2×8⇒x=83−8−16⇒x=83−(−16)⇒x=83+16⇒x=819⇒x=283
The number added to -2 to get 38\dfrac{3}{8}83 is 2382\dfrac{3}{8}283.
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What should be subtracted from -2 to get 38\dfrac{3}{8}83 ?
Evaluate:
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23+−45−13−25\dfrac{2}{3} + \dfrac{-4}{5} - \dfrac{1}{3} - \dfrac{2}{5}32+5−4−31−52