What should be added to −212-2\dfrac{1}{2}−221 to get −313-3\dfrac{1}{3}−331?
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Let xxx be added to −212-2\dfrac{1}{2}−221.
−212+x=−313⇒−52+x=−103⇒x=−103−−52-2\dfrac{1}{2} + x = -3\dfrac{1}{3}\\[1em] \Rightarrow -\dfrac{5}{2} + x = -\dfrac{10}{3}\\[1em] \Rightarrow x = -\dfrac{10}{3} - \dfrac{-5}{2}−221+x=−331⇒−25+x=−310⇒x=−310−2−5
LCM of 3 and 2 is 2 x 3 = 6
⇒x=−10×23×2−−5×32×3⇒x=−206−−156⇒x=−20−(−15)6⇒x=−20+156⇒x=−56\Rightarrow x = \dfrac{-10 \times 2}{3 \times 2} - \dfrac{-5 \times 3}{2 \times 3}\\[1em] \Rightarrow x = \dfrac{-20}{6} - \dfrac{-15}{6}\\[1em] \Rightarrow x = \dfrac{-20 - (-15)}{6}\\[1em] \Rightarrow x = \dfrac{-20 + 15}{6}\\[1em] \Rightarrow x = \dfrac{-5}{6}⇒x=3×2−10×2−2×3−5×3⇒x=6−20−6−15⇒x=6−20−(−15)⇒x=6−20+15⇒x=6−5
The number added to −212-2\dfrac{1}{2}−221 to get −313-3\dfrac{1}{3}−331 is −56\dfrac{-5}{6}6−5.
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Which should be subtracted from 2122\dfrac{1}{2}221 to get −313-3\dfrac{1}{3}−331 ?
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