Which term of A.P. 5, 15, 25, ……. will be 130 more than its 31^st term ?

In the A.P. 5, 15, 25, ……., a = 5 and d = 15 - 5 = 10.

Let n^th term be 130 more than 31^st term.

∴ a_n = 130 + a₃₁

⇒ a + (n - 1)d = 130 + a + (31 - 1)d

⇒ 5 + (n - 1)10 = 130 + 5 + 30(10)

⇒ 5 + 10n - 10 = 135 + 300

⇒ 10n - 5 = 435

⇒ 10n = 440

⇒ n = 44.

Hence, 44^th term of the A.P. will be 130 more than its 31^st term .