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Chemistry

Which will have greater volume when the following gases are compared at S.T.P.

(a) 1.2 lit N2 at 25°C and 748 mm Hg

(b) 1.25 lit O2 at S.T.P.?

Gas Laws

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Answer

1.2 lit N2 at 25°C and 748 mm Hg

Initial conditions :

P1 = Initial pressure of the gas = 748 mm Hg

V1 = Initial volume of the gas = 1.2 lit

T1 = Initial temperature of the gas = 25°C = 25 + 273 = 298 K

Final conditions :

P2 (Final pressure) = 760 mm of Hg

T2 (Final temperature) = 273 K

V2 (Final volume) = ?

By Gas Law:

P1×V1T1=P2×V2T2\dfrac{\text{P}1\times\text{V}1}{\text{T}1} = \dfrac{\text{P}2\times\text{V}2}{\text{T}2}

Substituting the values :

748×1.2298=760×V2273V2=748×1.2×273298×760V2=1.081 lit\dfrac{748 \times 1.2}{298} = \dfrac{760 \times \text{V}2}{273} \\[1em] \text{V}2 = \dfrac{748 \times 1.2\times 273}{298 \times 760} \\[1em] \text{V}_2 = 1.081 \space \text{lit} \\[1em]

∴ Volume of N2 at S.T.P. = 1.081 lit and volume of O2 at S.T.P. is 1.25 lit. Hence, volume of O2 at S.T.P. is greater than N2 at S.T.P.

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