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Mathematics

Without performing division, determine whether the decimal expansion of 18125\dfrac{18}{125} is terminating or non-terminating. If it terminates, state the number of decimal places.

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Answer

Given, 18125\dfrac{18}{125}

Prime factorisation of 125 = 53.

Since the denominator has only the prime factor 5, the decimal expansion is terminating.

To find the number of decimal places, we make the denominator a power of 10 by multiplying numerator and denominator by 23 = 8 :

18125=1853=18×2353×23=18×81000=1441000=0.144.\Rightarrow \dfrac{18}{125} = \dfrac{18}{5^3} = \dfrac{18 \times 2^3}{5^3 \times 2^3} = \dfrac{18 \times 8}{1000} = \dfrac{144}{1000} = 0.144.

The decimal expansion has 3 decimal places.

Hence, 18125\dfrac{18}{125} has a terminating decimal expansion of 3 decimal places.

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