Without using trigonometric tables, prove that: sec² 22° - cot² 68° = 1

Question

KnowledgeBoat · Accepted Answer

To prove, sec² 22° - cot² 68° = 1 Solving, L.H.S. of the equation we get : sec² 22° - cot² 68° ⇒ sec² 22° - cot² (90° - 22°) We know that, cot (90 - θ) = tan θ ⇒ sec² 22° - tan² 22° Since, L.H.S. = R.H.S. Hence, proved that sec² 22° - cot² 68° = 1.

Mathematics

Without using trigonometric tables, prove that:
sec² 22° - cot² 68° = 1

Trigonometrical Ratios

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sin 63° cos 27° + cos 63° sin 27° = 1

Without using trigonometric tables, prove that:
sec 31° sin 59° + cos 31° cosec 59° = 2.

Mathematics

Without using trigonometric tables, prove that:sec2 22° - cot2 68° = 1

Trigonometrical Ratios

Related Questions

Without using trigonometric tables, prove that:cos2 25° + cos2 65° = 1

Without using trigonometric tables, prove that:cosec2 67° - tan2 23° = 1

Without using trigonometric tables, prove that:sin 63° cos 27° + cos 63° sin 27° = 1

Without using trigonometric tables, prove that:sec 31° sin 59° + cos 31° cosec 59° = 2.

Without using trigonometric tables, prove that:
sec² 22° - cot² 68° = 1

Without using trigonometric tables, prove that:
cos² 25° + cos² 65° = 1

Without using trigonometric tables, prove that:
cosec² 67° - tan² 23° = 1

Without using trigonometric tables, prove that:
sin 63° cos 27° + cos 63° sin 27° = 1

Without using trigonometric tables, prove that:
sec 31° sin 59° + cos 31° cosec 59° = 2.