Mathematics
Without using trigonometric tables, prove that:
sin2 28° - cos2 62° = 0
Trigonometrical Ratios
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Answer
To prove,
sin2 28° - cos2 62° = 0.
Solving, L.H.S. of the equation.
sin2 28° - cos2 62°
= sin2 28° - cos2 (90° - 28°)
= sin2 28° - sin2 28°
= 0.
Since, L.H.S. = R.H.S.
Hence, proved that sin2 28° - cos2 62° = 0.
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