Chemistry
Write one equation in each case to show the action of sulphuric acid on:
(a) Calcium bicarbonate
(b) Sugar
(c) Sulphur
Sulphuric Acid
2 Likes
Answer
(a) Ca(HCO3)2 + H2SO4 ⟶ CaSO4 ↓ + 2H2O + 2CO2 ↑
(b)
(c) S + 2H2SO4 ⟶ 3SO2 + 2H2O
Answered By
1 Like
Related Questions
This question relates to the preparation of Nitric acid on a large scale.
(a) Name the reactant used in this process.
(b) State the conditions under which the reactions occur.
'M' is an element above lead in the activity series of metals. Select the correct answer in each case from (i) to (iii).
(a) M - 3e- ⟶ M3+: The process takes place by oxidation/reduction.
(b) M3+ ⟶ M: The cation gets reduced/oxidised to neutral atom.
(c) M reacts with dil. H2SO4 - to liberate hydrogen/sulphur dioxide gas.
Write the reaction taking place at the cathode and anode in the following process shown by a diagram.
In an Experiment, 6.21 g of lead is combined with 4.26 g of chlorine. What is the empirical formula of the resulting compound?