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(a) Write the relationship between resistivity and resistance of a cylindrical conductor of length l and area of cross-section A. Hence derive the SI unit of resistivity.

(b) Why are alloys used in electrical heating devices?

Current Electricity

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Answer

(a) Resistance of a cylindrical conductor is given by,

R=ρlA\text R = \text ρ \dfrac{\text l}{\text A}

Then,

SI unit of R=SI unit of ρ×SI unit of lSI unit of ASI unit of ρ=SI unit of R×SI unit of ASI unit of l=Ω×m2mSI unit of ρ=Ω.m\text {SI unit of R} = \text {SI unit of ρ} \times \dfrac{\text {SI unit of l}}{\text {SI unit of A}} \\[1em] \Rightarrow \text {SI unit of ρ} = \dfrac {\text {SI unit of R}\times \text {SI unit of A}}{\text {SI unit of l}} \\[1em] = \dfrac{\text Ω \times \text m^2 }{\text m} \\[1em] \Rightarrow \text {SI unit of ρ} = \text {Ω.m}

Hence, SI unit of ρ is Ω.m.

(b) Alloys are used in electrical heating devices because :

  • they have relatively high resistivity, so they produce a large amount of heat for a given current and voltage;
  • they have high melting points, so they do not melt at the high temperatures reached during heating;
  • they are resistant to oxidation and corrosion at high temperatures, so the heating element lasts longer;
  • their mechanical strength and ductility are suitable for making durable coils.

Pure metals (like copper) have low resistivity and oxidise or melt easily, so they are unsuited for heating elements.

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