Write the slope of the line whose inclination is:

(i) 0°

(ii) 30°

(iii) 45°

(iv) 60°

(i) 0°

The inclination of a line is 0°, then θ = 0°.

The slope of the line = m = tan 0° = 0

Hence, the slope of the line whose inclination is 0° is 0.

(ii) 30°

The inclination of a line is 30°, then θ = 30°.

The slope of the line = m = tan 30° = $\dfrac{1}{\sqrt3}$

Hence, the slope of the line whose inclination is 30° is $\dfrac{1}{\sqrt3}$.

(iii) 45°

The inclination of a line is 45°, then θ = 45°.

The slope of the line = m = tan 45° = 1

Hence, the slope of the line whose inclination is 45° is 1.

(iv) 60°

The inclination of a line is 60°, then θ = 60°.

The slope of the line = m = tan 60° = $\sqrt3$

Hence, the slope of the line whose inclination is 60° is $\sqrt3$.