If x = 2, y = 3 and z = 1, find the values of:

(i) x ÷ y

(ii) $\dfrac{xy}{z}$

(iii) $\dfrac{2x + 3y - 4z}{3x - z}$

(i) Substituting x = 2 and y = 3 in the given expression, we get:

x ÷ y

= 2 ÷ 3

∴ x ÷ y = $\dfrac{2}{3}$

(ii) Substituting x = 2, y = 3 and z = 1 in the given expression, we get:

$\dfrac{xy}{z}$

= $\dfrac{(2)(3)}{1}$

= $\dfrac{6}{1}$

∴ $\dfrac{xy}{z}$ = 6

(iii) Substituting x = 2, y = 3 and z = 1 in the given expression, we get:

$\Rightarrow \dfrac{2x + 3y - 4z}{3x - z} \\[1em] = \dfrac{2(2) + 3(3) - 4(1)}{3(2) - 1} \\[1em] = \dfrac{4 + 9 - 4}{6 - 1} \\[1em] = \dfrac{9}{5} = 1\dfrac{4}{5}$

∴ $\dfrac{2x + 3y - 4z}{3x - z}$ = $\dfrac{9}{5} = 1\dfrac{4}{5}$