$\Big(\dfrac{10}{3}xy^2z\Big)$ x $\Big(-\dfrac{9}{5}x^2z\Big)$ is equal io:

1. - 6x³y²z²

2. 6x³y²z²

3. $-\dfrac{2}{3}x^2y^2z^2$

4. $\dfrac{9}{5}xy^3z^2$

$\Big(\dfrac{10}{3}xy^2z\Big) \times \Big(-\dfrac{9}{5}x^2z\Big)\\[1em] = \Big(-\dfrac{10 \times 9}{3 \times 5}x^{1+2}y^2z^{1+1}\Big)\\[1em] = \Big(-\dfrac{90}{15}x^{3}y^2z^{2}\Big)\\[1em] = (-6x^3y^2z^2)$

Hence, option 1 is the correct option.