(x + y)(x - y)(x^2 + y^2)(x^4 + y^4) is equal to: 1. x^4 + y^4 2. x^8 + y^8 3. x^8 - y^8 4. 2x^6y^6

Using the formula, [∵(x \- y)(x \+ y) = x 2 \- y 2 ] (x \+ y)(x \- y)(x 2 \+ y 2 )(x 4 \+ y 4 ) ⇒ [(x \+ y)(x \- y)](x 2 \+ y 2 )(x 4 \+ y 4 ) ⇒ [(x 2 \- y 2 )(x 2 \+ y 2 )](x 4 \+ y 4 ) ⇒ [(x 4 \- y 4 )(x 4 \+ y 4 )] ⇒ (x 8 \- y 8 ) Hence, option 3 is the correct option.

Mathematics

(x + y)(x - y)(x² + y²)(x⁴ + y⁴) is equal to:
x⁴ + y⁴
x⁸ + y⁸
x⁸ - y⁸
2x⁶y⁶

Identities

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Answer

Using the formula,

[∵(x - y)(x + y) = x² - y²]

(x + y)(x - y)(x² + y²)(x⁴ + y⁴)

⇒ [(x + y)(x - y)](x² + y²)(x⁴ + y⁴)

⇒ [(x² - y²)(x² + y²)](x⁴ + y⁴)

⇒ [(x⁴ - y⁴)(x⁴ + y⁴)]

⇒ (x⁸ - y⁸)

Hence, option 3 is the correct option.

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Mathematics

(x + y)(x - y)(x² + y²)(x⁴ + y⁴) is equal to:
x⁴ + y⁴
x⁸ + y⁸
x⁸ - y⁸
2x⁶y⁶

Identities

Answer

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(x + y)(x - y)(x² + y²)(x⁴ + y⁴) is equal to:
x⁴ + y⁴
x⁸ + y⁸
x⁸ - y⁸
2x⁶y⁶

The sum of the squares of two numbers is 13 and their product is 6. Find :
(i) the sum of the two numbers.
(ii) the difference between them.

If a is a positive and $a^2 +\dfrac{1}{a^2}= 18$ ; then the value of $a -\dfrac{1}{a}$ is:
4
16
20
2√5

The value of 102 x 98 is:
6999
6696
9696
9996

(x + 3) (x + 3) - (x - 2) (x - 2) is equal to:
10x + 5
10x - 5
5 - 10x
none of these