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Mathematics

If x ∈ Z+, find the solution set of each of the following inequations. Represent each solution set on the number line.

(i) 7x < 17

(ii) 4x - 11 < 5

(iii) 8 - x > 13\dfrac{1}{3}

(iv) 4(x + 5) < 29

(v) 5 > 23\dfrac{2}{3}x

(vi) 2 - 7x29\dfrac{7x}{29} < 53\dfrac{5}{3}

Linear Inequations

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Answer

(i) 7x < 17

We have:

7x < 17

⇒ x < 177[Dividing both sides by 7]\dfrac{17}{7} \quad \text{[Dividing both sides by 7]}

⇒ x < 2.42…

Positive integers less than 2.42… are {1, 2}

∴ Solution set = {1, 2}

find the solution set of each of the following inequations. Represent each solution set on the number line. R.S. Aggarwal Mathematics Solutions ICSE Class 7.

(ii) 4x - 11 < 5

We have:

4x - 11 < 5

⇒ 4x < 5 + 11 \quad [Adding 11 on both sides]

⇒ 4x < 16

⇒ x < 164[Dividing both sides by 4]\dfrac{16}{4} \quad \text{[Dividing both sides by 4]}

⇒ x < 4

Positive integers less than 4 are {1, 2, 3}

∴ Solution set = {1, 2, 3}

find the solution set of each of the following inequations. Represent each solution set on the number line. R.S. Aggarwal Mathematics Solutions ICSE Class 7.

(iii) 8 - x > 13\dfrac{1}{3}

We have:

=8x>13x>138[Subtracting 8 from both sides]x>1243x>233x>7.66…x<7.66…[Multiplying -1 on both sides and reversing the sign]\phantom{=} 8 - x \gt \dfrac{1}{3} \\[1em] \Rightarrow -x \gt \dfrac{1}{3} - 8 \quad \text{[Subtracting 8 from both sides]} \\[1em] \Rightarrow -x \gt \dfrac{1 - 24}{3} \\[1em] \Rightarrow -x \gt \dfrac{-23}{3} \\[1em] \Rightarrow -x \gt -7.66… \\[1em] \Rightarrow x \lt 7.66… \quad \text{[Multiplying -1 on both sides and reversing the sign]}

Positive integers less than 7.66.. are {1, 2, 3, 4, 5, 6, 7}

∴ Solution set = {1, 2, 3, 4, 5, 6, 7}

find the solution set of each of the following inequations. Represent each solution set on the number line. R.S. Aggarwal Mathematics Solutions ICSE Class 7.

(iv) 4(x + 5) < 29

We have:

4(x + 5) < 29

⇒ 4x + 20 < 29

⇒ 4x < 29 - 20 \quad [Subtracting 20 from both sides]

⇒ 4x < 9

⇒ x < 94[Dividing both sides by 4]\dfrac{9}{4} \quad \text{[Dividing both sides by 4]}

⇒ x < 2.25

Positive integers less than 2.25 are {1, 2}

∴ Solution set = {1, 2}

find the solution set of each of the following inequations. Represent each solution set on the number line. R.S. Aggarwal Mathematics Solutions ICSE Class 7.

(v) 5 > 23\dfrac{2}{3}x

We have:

5 > 23\dfrac{2}{3}x

⇒ 5 x 3 > 2x \quad [Multiplying 3 on both sides]

⇒ 15 > 2x

152\dfrac{15}{2} > x \quad [Dividing both sides by 2]

⇒ 7.5 > x

⇒ x < 7.5

Positive integers less than 7.5 are {1, 2, 3, 4, 5, 6, 7}

∴ Solution set = {1, 2, 3, 4, 5, 6, 7}

find the solution set of each of the following inequations. Represent each solution set on the number line. R.S. Aggarwal Mathematics Solutions ICSE Class 7.

(vi) 2 - 7x29\dfrac{7x}{29} < 53\dfrac{5}{3}

We have:

=27x29<537x29<532[Subtracting 2 from both sides]7x29<5637x29<13x<13×297[Multiplying297 on both sides ]x<2921x<1.38…x>1.38[Multiplying -1 on both sides and reversing the sign]\phantom{=} 2 - \dfrac{7x}{29} \lt \dfrac{5}{3} \\[1em] \Rightarrow -\dfrac{7x}{29} \lt \dfrac{5}{3} - 2 \quad \text{[Subtracting 2 from both sides]} \\[1em] \Rightarrow -\dfrac{7x}{29} \lt \dfrac{5 - 6}{3} \\[1em] \Rightarrow -\dfrac{7x}{29} \lt \dfrac{-1}{3} \\[1em] \Rightarrow -x \lt \dfrac{-1}{3} \times \dfrac{29}{7} \quad \text{[Multiplying} \dfrac{29}{7} \text{ on both sides ]} \\[1em] \Rightarrow -x \lt \dfrac{-29}{21} \\[1em] \Rightarrow -x \lt - 1.38… \\[1em] \Rightarrow x \gt 1.38 \quad \text{[Multiplying -1 on both sides and reversing the sign]}

Positive integers greater than 1.38 are {2, 3, 4, 5, …}

∴ Solution set = {2, 3, 4, 5, …}

find the solution set of each of the following inequations. Represent each solution set on the number line. R.S. Aggarwal Mathematics Solutions ICSE Class 7.

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