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Mathematics

13\dfrac{1}{3} x2 - 2x - 9 is equal to:

  1. 13\dfrac{1}{3} (x - 9)(x + 3)

  2. 13\dfrac{1}{3} (x - 9)(x - 3)

  3. 13\dfrac{1}{3} (x + 9)(x - 3)

  4. 13\dfrac{1}{3} (x + 9)(x + 3)

Factorisation

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Answer

Given,

13x22x913x263x27313(x26x27)13(x29x+3x27)13[x(x9)+3(x9)]13(x9)(x+3)\dfrac{1}{3} x^2 - 2x - 9\\[1em] \Rightarrow \dfrac{1}{3} x^2 - \dfrac{6}{3}x - \dfrac{27}{3}\\[1em] \Rightarrow \dfrac{1}{3} (x^2 - 6x - 27)\\[1em] \Rightarrow \dfrac{1}{3} (x^2 - 9x + 3x - 27)\\[1em] \Rightarrow \dfrac{1}{3} [x(x - 9) + 3(x - 9)]\\[1em] \Rightarrow \dfrac{1}{3} (x - 9)(x + 3)

Hence, option 1 is the correct option.

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