(xa)(b - c) (xb)(c - a)(xc)(a - b) =
0
1
2
3
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Given,
⇒ (xa)(b - c)(xb)(c - a)(xc)(a - b)
⇒ x(ab - ac)x(bc - ba)x(ca - cb)
⇒ x(ab - ac) + (bc - ba) + (ca - cb)
⇒ x(ab - ac + bc - ba + ca - cb)
⇒ x(ab - ab + bc -bc - ac + ac)
⇒ x0
⇒ 1.
Hence, option 2 is the correct option.
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