Factorise : x^2 + 6xy + 9y^2 + x + 3y

Question

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x² \+ 6xy \+ 9y² \+ x \+ 3y Using the formula [∵ (x \+ y)² = x² \+ y² \+ 2xy] = (x² \+ 6xy \+ 9y²) \+ x \+ 3y = ((x)² \+ 2 x 3y \+ (3y)²) \+ x \+ 3y = (x \+ 3y)² \+ (x \+ 3y) = (x \+ 3y)((x \+ 3y) \+ 1) = (x \+ 3y)(x \+ 3y \+ 1) Hence,x² \+ 6xy \+ 9y² \+ x \+ 3y = (x \+ 3y)(x \+ 3y \+ 1)

Mathematics

Factorise :
x² + 6xy + 9y² + x + 3y

Factorisation

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Mathematics

Factorise :x2 + 6xy + 9y2 + x + 3y

Factorisation

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Factorise :5ap2 + 11ap + 2a

Factorise :a2 + 2ab + b2 - c2

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Factorise :
x² + 6xy + 9y² + x + 3y

Factorise :
5ap² + 11ap + 2a

Factorise :
a² + 2ab + b² - c²

Factorise :
4a² - 12ab + 9b² + 4a - 6b

Factorise :
2a²b² - 98b⁴