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In the year 2024-25 period, India collected approximately 1.46 crore (14.6 million) units of blood, which was about 15% more than the previous year. This volume is roughly equal to the estimated annual national requirement, indicating progress toward meeting demand. The Indian Red Cross Society (IRCS) typically collects around 30,000 units per year as per the report in 2024-25.

In the year 2024-25 period, India collected approximately 1.46 crore (14.6 million) units of blood, which was about 15% more than the previous year. This volume is roughly equal to the estimated annual national requirement, indicating progress toward meeting demand. The Indian Red Cross Society (IRCS) typically collects around 30,000 units per year as per the report in 2024-25. Compound Interest (Stage 2) [Applications], Concise Mathematics Solutions ICSE Class 9.

Based on the above information, answer the following :

(i) If the number of blood donors increases by 15% every year, then what will be the number of units to be collected by IRCS in the year 2026-27.

(ii) If 2024-25 is taken as a base year and it is predicted that the number of units to be collected by IRCS in 3 years will be 39,930, then what will be rate of increase of donors?

Compound Interest

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Answer

(i) Given,

Units collected by IRCS in 2024-25 = 30,000

Increase rate = 15% per year

From 2024-25 to 2026-27 = 2 years

By formula, A = P(1+r100)P\Big(1 + \dfrac{r}{100}\Big)n

A=30000(1+15100)2A=30000(1+0.15)2A=30000(1.15)2A=30000×1.3225A=39,675 units\Rightarrow A = 30000 \Big(1 + \dfrac{15}{100}\Big)^2 \\[1em] \Rightarrow A = 30000(1 + 0.15)^2 \\[1em] \Rightarrow A = 30000(1.15)^2 \\[1em] \Rightarrow A = 30000 × 1.3225 \\[1em] \Rightarrow A = 39,675 \text { units}

Hence, in 2026-27 number of units collected = 39,675 units.

(ii) Given,

Initial (P) = 30,000

Final (A) = 39,930

Time (n) = 3 years

By formula, A = P(1+r100)P\Big(1 + \dfrac{r}{100}\Big)n

39930=30000(1+r100)33993030000=(1+r100)31.331=(1+r100)31+r100=1.33131+r100=1.1r100=0.1r=100×0.1r=10%.\Rightarrow 39930 = 30000 \Big(1 + \dfrac{r}{100}\Big)^3 \\[1em] \Rightarrow \dfrac{39930}{30000} = \Big(1 + \dfrac{r}{100}\Big)^3 \\[1em] \Rightarrow 1.331 = \Big(1 + \dfrac{r}{100}\Big)^3 \\[1em] \Rightarrow 1 + \dfrac{r}{100} = \sqrt[3]{1.331} \\[1em] \Rightarrow 1 + \dfrac{r}{100} = 1.1 \\[1em] \Rightarrow \dfrac{r}{100} = 0.1 \\[1em] \Rightarrow r = 100 × 0.1 \\[1em] \Rightarrow r = 10\%.

Hence, rate of increase = 10%.

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