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Chapter 11

Simple Interest — Multiple Choice Questions

Class - 7 Concise Mathematics Selina



Multiple Choice Questions

Question 1

Sangeeta deposited ₹ 1,000 in a bank paying interest at the rate of 10% per year. The amount in 2 years is:

  1. ₹ 200

  2. ₹ 800

  3. ₹ 1,200

  4. ₹ 1,100

Answer

P = ₹ 1,000, R = 10% and T = 2 years.

I = 1000×10×2100\dfrac{1000 \times 10 \times 2}{100} = ₹ 200.

Amount = P + I = 1,000 + 200 = ₹ 1,200.

Hence, option 3 is the correct option.

Question 2

Mercy invested ₹ 2,000 at 12% per year and an equal sum at 10% per year. Thus, total income from interest in one year is:

  1. ₹ 440

  2. ₹ 40

  3. ₹ 240

  4. ₹ 200

Answer

Interest on ₹ 2,000 at 12% for 1 year = 2000×12×1100\dfrac{2000 \times 12 \times 1}{100} = ₹ 240.

Interest on ₹ 2,000 at 10% for 1 year = 2000×10×1100\dfrac{2000 \times 10 \times 1}{100} = ₹ 200.

Total income from interest = 240 + 200 = ₹ 440.

Hence, option 1 is the correct option.

Question 3

Mercy invested ₹ 5,000 at 12% per year and an equal sum at 10% per year. The difference of incomes from two investments in 2 years is:

  1. ₹ 1,200

  2. ₹ 1,000

  3. ₹ 200

  4. ₹ 2,200

Answer

Interest on ₹ 5,000 at 12% for 2 years = 5000×12×2100\dfrac{5000 \times 12 \times 2}{100} = ₹ 1,200.

Interest on ₹ 5,000 at 10% for 2 years = 5000×10×2100\dfrac{5000 \times 10 \times 2}{100} = ₹ 1,000.

Difference of incomes = 1,200 − 1,000 = ₹ 200.

Hence, option 3 is the correct option.

Question 4

A sum of money invested for 10 years earns interest equal to the sum itself. The rate of interest is:

  1. 5%

  2. 10%

  3. 20%

  4. none of these

Answer

Let the sum be ₹ P and T = 10 years.

I = the sum itself = ₹ P.

R = I×100P×T\dfrac{\text{I} \times 100}{\text{P} \times \text{T}}%

=P×100P×10= \dfrac{\text{P} \times 100}{\text{P} \times 10}%

= 10%.

Hence, option 2 is the correct option.

Question 5

A sum of money invested at 5% per year, earns interest equal to half of the sum invested. The time for which the sum is invested, is:

  1. 5 years

  2. 10 years

  3. 15 years

  4. 20 years

Answer

Let the sum be ₹ P and R = 5%.

I = half of the sum = ₹ P2\dfrac{\text{P}}{2}.

 T =I×100P×R=P2×100P×5=1002×5=10 years \text{ T } = \dfrac{\text{I} \times 100}{\text{P} \times \text{R}}\\[1em] = \dfrac{\dfrac{\text{P}}{2} \times 100}{\text{P} \times 5}\\[1em] = \dfrac{100}{2 \times 5}\\[1em] = 10 \text{ years }

Hence, option 2 is the correct option.

Question 6

A sum of money invested at 10% per annum, earns interest which is 1.2 times the sum invested. The time, for which the sum is invested, is:

  1. 8 years

  2. 10 years

  3. 12 years

  4. 20 years

Answer

Let the sum be ₹ P and R = 10%.

I = 1.2 times the sum = ₹ 1.2P.

 T =I×100P×R=1.2P×100P×10=12010=12 years\text{ T }= \dfrac{\text{I} \times 100}{\text{P} \times \text{R}}\\[1em] = \dfrac{1.2\text{P} \times 100}{\text{P} \times 10}\\[1em] = \dfrac{120}{10}\\[1em] = 12\text{ years}

Hence, option 3 is the correct option.

Question 7

A sum of money invested at 10% per annum becomes 1.2 times the sum invested. The time, for which the sum is invested, is:

  1. 2 years

  2. 4 years

  3. 6 years

  4. 8 years

Answer

Let the sum be ₹ P and R = 10%.

Amount = 1.2 times the sum = ₹ 1.2P.

I = Amount − P = 1.2P − P = ₹ 0.2P.

 T =I×100P×R=0.2P×100P×10=2010=2 years\text{ T }= \dfrac{\text{I} \times 100}{\text{P} \times \text{R}}\\[1em] = \dfrac{0.2\text{P} \times 100}{\text{P} \times 10}\\[1em] = \dfrac{20}{10}\\[1em] = 2\text{ years}

Hence, option 1 is the correct option.

Question 8

In 8 years, a sum earns interest equal to the sum invested. The rate of interest is:

  1. 7.5%

  2. 8%

  3. 10%

  4. 12.5%

Answer

Let the sum be ₹ P and T = 8 years.

I = the sum invested = ₹ P.

R = I×100P×T\dfrac{\text{I} \times 100}{\text{P} \times \text{T}}%

=P×100P×8= \dfrac{\text{P} \times 100}{\text{P} \times 8}%

=1008= \dfrac{100}{8}%

= 12.5%

Hence, option 4 is the correct option.

Question 9

A sum of money invested at 10% per annum becomes ₹ 3,000 in 5 years. The sum invested is:

  1. ₹ 1,000

  2. ₹ 1,500

  3. ₹ 2,000

  4. ₹ 4,000

Answer

Let the sum be ₹ P, R = 10% and T = 5 years.

I = P×10×5100=P2\dfrac{\text{P} \times 10 \times 5}{100} = \dfrac{\text{P}}{2}.

Amount = P + I

3000=P+P23000=3P2P=3000×23=₹ 2,000\Rightarrow 3000 = \text{P} + \dfrac{\text{P}}{2}\\[1em] \Rightarrow 3000 = \dfrac{3\text{P}}{2}\\[1em] \Rightarrow \text{P} = \dfrac{3000 \times 2}{3} = ₹\ 2,000

Hence, option 3 is the correct option.

Question 10

₹ 4,000 becomes ₹ 5,000 in 5 years. The rate of interest is:

  1. 5%

  2. 10%

  3. 12%

  4. none of these

Answer

P = ₹ 4,000, Amount = ₹ 5,000 and T = 5 years.

I = Amount − P = 5,000 − 4,000 = ₹ 1,000.

R = I×100P×T\dfrac{\text{I} \times 100}{\text{P} \times \text{T}}%

=1000×1004000×5= \dfrac{1000 \times 100}{4000 \times 5}%

=10000020000= \dfrac{100000}{20000}%

=102= \dfrac{10}{2}%

= 5%.

Hence, option 1 is the correct option.

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