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Chapter 11

Simple Interest — Statement I-II Type Questions

Class - 7 Concise Mathematics Selina



Statement I-II Type Questions

Question 11

Statement 1: ₹ 400 will yield an interest of ₹ 36 in 3 years at 3% p.a.

Statement 2: Rate percent is the interest paid on ₹ 100 for any period of time.

Which of the following options is correct?

  1. Both the statements are true.

  2. Both the statements are false.

  3. Statement 1 is true, and statement 2 is false.

  4. Statement 1 is false, and statement 2 is true.

Answer

Solving,

 I =P×R×T100=400×3×3100=3600100=₹ 36\text{ I }= \dfrac{\text{P} \times \text{R} \times \text{T}}{100}\\[1em] = \dfrac{400 \times 3 \times 3}{100}\\[1em] = \dfrac{3600}{100}\\[1em] = ₹\ 36

So, Statement 1 is true.

Rate percent (per annum) is the interest on ₹ 100 for a specific period of time, not for any period of time.

So, Statement 2 is false.

Hence, option 3 is the correct option.

Question 12

Statement 1: If both rate percent and time are equal, then simple interest on a certain sum is 1625\dfrac{16}{25} times of the sum.

Statement 2: The value of interest depends on (i) Sum, (ii) Rate of interest p.a. and (iii) time in years.

Which of the following options is correct?

  1. Both the statements are true.

  2. Both the statements are false.

  3. Statement 1 is true, and statement 2 is false.

  4. Statement 1 is false, and statement 2 is true.

Answer

Let the sum be ₹ P and rate = time = n.

Then I = P×n×n100=n2P100\dfrac{\text{P} \times n \times n}{100} = \dfrac{n^2\text{P}}{100}.

This equals 1625\dfrac{16}{25} times the sum only when n2P100=16P25\dfrac{n^2 \text {P}}{100} = \dfrac{16 \text{P}}{25}, i.e. n = 8. For any other equal values of rate and time (say n = 5), the interest is not 1625\dfrac{16}{25} of the sum.

So, Statement 1 is false.

Since I = P×R×T100\dfrac{\text{P} \times \text{R} \times \text{T}}{100}, the interest depends on the Sum, the Rate of interest p.a. and the time in years.

So, Statement 2 is true.

Hence, option 4 is the correct option.

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