Sum of digits of a two digit number is 8. If the number obtained by reversing the digits is 18 more than the original number, then the original number is
35
53
26
62
Answer
Let the digit at ten's place be x and digit at one's place be y.
Given, sum of digits = 8.
x + y = 8 .......(i)
Number = 10 × x + y = 10x + y
On reversing digits number = 10 × y + x = 10y + x.
Given, number obtained by reversing the digits is 18 more than the original number.
⇒ 10y + x = 10x + y + 18
⇒ 10y - y + x - 10x = 18
⇒ 9y - 9x = 18
⇒ y - x = 2 .........(ii)
Adding (i) and (ii) we get,
⇒ x + y + (y - x) = 8 + 2
⇒ 2y = 10
⇒ y = 5.
Substituting value of y in (i) we get,
⇒ x + 5 = 8
⇒ x = 3.
Number = 10x + y = 10(3) + 5 = 35.
Hence, Option 1 is the correct option.
The sum of two natural numbers is 25 and their difference is 7. The numbers are
17 and 8
16 and 9
18 and 7
15 and 10
Answer
Let the two numbers be x and y.
Given, sum = 25.
x + y = 25 ........(i)
Given, difference = 7.
x - y = 7 .......(ii)
Adding (i) and (ii) we get,
⇒ (x + y) + (x - y) = 25 + 7
⇒ 2x = 32
⇒ x = 16.
Substituting value of x in (i) we get,
⇒ 16 + y = 25
⇒ y = 9.
Hence, Option 2 is the correct option.
The sum of two natural numbers is 240 and their ratio is 3 : 5. Then the greater number is
180
160
150
90
Answer
Let the two numbers be x and y.
Given, sum = 240.
∴ x + y = 240
⇒ x = 240 - y ........(i)
......(ii)
Substituting value of x from (i) in (ii) we get,
Substituting value of y in (i) we get,
⇒ x = 240 - 150 = 90.
Hence, Option 3 is the correct option.
The sum of the digits of a two digit number is 9. If 27 is added to it, the digits of the number get reversed. The number is
27
72
63
36
Answer
Let the digit at ten's place be x and digit at one's place be y.
Given, sum of digits = 9.
⇒ x + y = 9 .......(i)
Number = 10 × x + y = 10x + y
On reversing digits, number = 10 × y + x = 10y + x.
⇒ 10x + y + 27 = 10y + x
⇒ 10x - x + y - 10y + 27 = 0
⇒ 9x - 9y + 27 = 0
⇒ 9(x - y + 3) = 0
⇒ x - y + 3 = 0
⇒ y - x = 3 .......(ii)
Adding (i) and (ii) we get,
⇒ x + y + (y - x) = 9 + 3
⇒ 2y = 12
⇒ y = 6.
Substituting value of y in (i) we get,
⇒ x + 6 = 9
⇒ x = 3.
Number = 10 × x + y = 10 × 3 + 6 = 36.
Hence, Option 4 is the correct option.
The sum of the digits of a two digit number is 12. If the number is decreased by 18, its digits get reversed. The number is
48
84
57
75
Answer
Let the digit at ten's place be x and digit at one's place be y.
Given, sum of digits = 12.
x + y = 12 .......(i)
Number = 10 × x + y = 10x + y
On reversing digits, number = 10 × y + x = 10y + x.
⇒ 10x + y - 18 = 10y + x
⇒ 10x - x + y - 10y - 18 = 0
⇒ 9x - 9y = 18
⇒ 9(x - y) = 18
⇒ x - y = 2 .......(ii)
Adding (i) and (ii) we get,
⇒ x + y + (x - y) = 12 + 2
⇒ 2x = 14
⇒ x = 7.
Substituting value of x in (i) we get,
⇒ 7 + y = 12
⇒ y = 5.
Number = 10 × x + y = 10 × 7 + 5 = 75.
Hence, Option 4 is the correct option.
Aruna has only ₹1 and ₹2 coins with her. If the total number of coins that she has is 50 and the amount of the money with her is ₹75, then the number of ₹1 and ₹2 coins are respectively
35 and 15
35 and 20
15 and 75
25 and 25
Answer
Let ₹1 coins be x and ₹2 coins be y.
According to first condition,
x + y = 50 .......(i)
According to second condition,
1.x + 2.y = 75
x + 2y = 75 ......(ii)
Subtracting (i) from (ii) we get,
⇒ x + 2y - (x + y) = 75 - 50
⇒ 2y - y = 25
⇒ y = 25.
Substituting value of y in (i) we get,
⇒ x + 25 = 50
⇒ x = 25.
Hence, Option 4 is the correct option.
The age of a woman is four times the age of her daughter. Five years hence, the age of the woman will be three times the age of her daughter. The present age of the daughter is
40 years
20 years
15 years
10 years
Answer
Let age of daughter be x years so, the age of woman is 4x years.
After 5 years,
Age of daughter = (x + 5) years
Age of woman = (4x + 5) years.
According to question,
⇒ 4x + 5 = 3(x + 5)
⇒ 4x + 5 = 3x + 15
⇒ 4x - 3x = 15 - 5
⇒ x = 10.
Hence, Option 4 is the correct option.
Father's age is six times his son's age. Four years hence, the age of the father will be four times his son's age. The present age in years of the son and the father are, respectively,
4 and 24
5 and 30
6 and 36
3 and 24
Answer
Let age of son be x years so, the age of father is 6x years.
After 4 years,
Age of son = (x + 4) years
Age of father = (6x + 4) years.
According to question,
⇒ 6x + 4 = 4(x + 4)
⇒ 6x + 4 = 4x + 16
⇒ 2x = 16 - 4
⇒ 2x = 12
⇒ x = 6.
Age of father = 6x = 36.
Hence, Option 3 is the correct option.
Consider the following two statements:
Statement 1: A husband is 2 years older than his wife, and sum of their ages is 52 years. Then the wife is 25 years old.
Statement 2: A father is twice as old as his daughter, and difference of their ages is 26 years. Then the father is 50 years old.
Which of the following is valid?
Both the statements are true.
Both the statements are false.
Statement 1 is true, and Statement 2 is false.
Statement 1 is false, and Statement 2 is true.
Answer
Let x years be the husband's age and y years be the wife's age.
Given,
Husband is 2 years older than his wife.
⇒ x = y + 2 ..................(1)
Sum of husband's age and wife's age = 52 years
⇒ x + y = 52 ..................(2)
Substituting the value of x from equation (1) in equation (2), we get
⇒ (y + 2) + y = 52
⇒ 2y + 2 = 52
⇒ 2y = 52 - 2
⇒ 2y = 50
⇒ y =
⇒ y = 25 years.
∴ Statement 1 is true.
Let the age of daughter be a years.
Given,
Father's age is twice that of daughter's age.
Father's age = 2a years
Difference of father's age and daughter's age = 26 years
⇒ 2a - a = 26
⇒ a = 26
Father's age = 2a = 2 x 26 = 52 years.
∴ Statement 2 is true.
∴ Both the statements are true.
Hence, option 1 is the correct option.